How do you simplify $Ln(e^-2)$ ?

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Answer 1 · 2016-10-08T08:03:18

$ln(e^(-2))=-2$

$ln$ denotes natural logarithm i.e. to the base $e$

Hence $ln(e^(-2))$

= $(-2)xxlne$

= $(-2)xx1$

= $-2$

How do you simplify Ln(e^-2)Ln(e^-2)?