How do you simplify #lne^lnx#?

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Answer 1 · 2018-04-03T13:09:18

#lne^lnx=lnx#

As #lna^b=b*lna#,

#lne^lnx=lnx*lne#

but as base in #lnx# is #e#, #lne=1#

hence #lne^lnx=lnx#

Answer 2 · 2018-04-03T13:19:23

#lnx#

it's known that:
#lne^lnx#=#lnx*lne#
And
#lne=1#
#therefore##lne^lnx=lnx#