How do you simplify #\log _ { y } ( 2x ^ { 2} y z ) ^ { 5}#?
1 Answer
Sep 11, 2017
Explanation:
#= 5log_y(2x^2yz)#
#= 5log_y(2x^2) + 5log_y y + 5log_y z#
#=10log_y (2x) + 5 + 5log_y z#
#= 5 + 10log_y(2x) + 5log_y z#
Hopefully this helps!
