# How do you simplify  (-m^2n^4 times -mn^-2)^5?

##### 1 Answer
May 31, 2016

${m}^{15} {n}^{10}$

#### Explanation:

First multiply the two terms in the parentheses keeping in mind that you add the exponents of terms with the same base.

${\left({\left(- 1\right)}^{2} {m}^{2 + 1} {n}^{4 - 2}\right)}^{5} = {\left({m}^{3} {n}^{2}\right)}^{5}$

Now distribute the fifth power to each term in the parentheses keeping in mind that you multiply each term by the power.

${m}^{3 \cdot 5} {n}^{2 \cdot 5} = {m}^{15} {n}^{10}$