How do you simplify $m^{4} \div m$ $m^4 div m$ ?

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Answer 1 · 2018-03-28T17:47:34

$m^{3}$ $m^3$

$\frac{m^{4}}{m}$ $(m^4)/m$

$\frac{m \cdot m \cdot m \cdot m}{m}$ $(m*m*m*m)/m$ (One m on the top and one m on the bottom cancel each other out)

$m \cdot m \cdot m$ $m*m*m$ = $m^{3}$ $m^3$

Answer 2 · 2018-03-28T17:52:14

Rebember: $\frac{1}{a} = a^{- 1}$ $1/a=a^(-1)$

$\frac{m^{4}}{m} = m^{4 - 1} = m^{3}$ $m^4/m=m^(4-1)=m^3$
For more: Exponentiation (see section: Integer exponents, Identities and properties)

How do you simplify m4÷mm^4 div m ?