How do you simplify #(m^4p^2)/(m^2p)#?

1 Answer
Feb 12, 2017

Answer:

See the entire simplification process below:

Explanation:

Use these two rules of exponents to simplify this expression:

#a = a^color(red)(1)# and #(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))#

#(m^color(red)(4)p^color(red)(2))/(m^color(blue)(2)p^color(blue)(1)) = m^(color(red)(4)-color(blue)(2))p^(color(red)(2)-color(blue)(1)) = m^2p^1 = m^2p#