# How do you simplify (m^5)^2/m^-8?

Jul 8, 2016

${m}^{18}$

#### Explanation:

To simplify ${\left({m}^{5}\right)}^{2} / {m}^{-} 8$

Begin by multiplying the two exponents on the numerator

${m}^{10} / {m}^{-} 8$

In order to eliminate the negative exponent in the denominator move the term to the numerator

${m}^{10} {m}^{8}$

Now multiply the terms by adding the exponents

${m}^{10 + 8}$

${m}^{18}$

Jul 8, 2016

${m}^{18}$

#### Explanation:

Using the $\textcolor{b l u e}{\text{laws of exponents}}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminders}}$

•(a^m)^n=a^(mn)........ (1)

•a^m/a^n=a^(m-n)........ (2)

Using (1) : ${\left({m}^{5}\right)}^{2} = {m}^{5 \times 2} = {m}^{10}$

Using (2): m^(10)/m^(-8)=m^(10-(-8)=m^(10+8)=m^(18)