# How do you simplify (m^6) ^ (-2/3)?

= $\frac{1}{m} ^ 4$
${\left({\left(m\right)}^{a}\right)}^{b}$ = ${m}^{a \cdot b}$. Applying this formula, we get:
${\left({m}^{6}\right)}^{- \frac{2}{3}}$ = ${m}^{6 \cdot - \frac{2}{3}}$ = ${m}^{2 \cdot - 2}$= ${m}^{- 4}$ = $\frac{1}{m} ^ 4$