# How do you simplify m/m^3 ?

May 2, 2015

${m}^{3} = {m}^{1 + 2} = {m}^{1} \times {m}^{2} = m \times {m}^{2}$

$\implies \frac{m}{m} ^ 3 = \frac{\cancel{m}}{\cancel{m} \times {m}^{2}} = \frac{1}{m} ^ 2 = {m}^{-} 2$

May 2, 2015

By considering that ${m}^{3}$ is nothing else than $m \cdot m \cdot m$

$\frac{m}{m} ^ 3 = \frac{m}{m \cdot m \cdot m}$

You can cancel the $m$ above against one of the $m$'s below.

$= \frac{1}{m \cdot m} = \frac{1}{m} ^ 2$