How do you simplify (n^-1)^4/n^4 and write it using only positive exponents?

Aug 22, 2016

$\frac{1}{n} ^ 8$

Explanation:

In the same way that $\frac{2}{3} = 2 \times \frac{1}{3} \text{ }$ split $\text{ } \frac{{\left({n}^{- 1}\right)}^{4}}{n} ^ 4$

${\left({n}^{- 1}\right)}^{4} \times \frac{1}{n} ^ 4$

But $\text{ } {n}^{- 1} \to \frac{1}{n}$ so ${\left({n}^{- 1}\right)}^{4} = {\left(\frac{1}{n}\right)}^{4} = \frac{1}{n} ^ 4$

Hence:

$\frac{{\left({n}^{- 1}\right)}^{4}}{n} ^ 4 \text{ " =" " 1/n^4xx1/n^4" "=" } \frac{1}{n} ^ 8$