Question

How do you simplify `(n-1)!(n^2+n)`?

Answer 1

`(n-1)!(n^2+n)=(n+1)!`

Explanation:

`(n-1)!(n^2+n)`

= `(n-1)!×n×(n+1)`

= `(n+1)×n×(n-1)!`

= `(n+1)×n×(n-1)×(n-2)×(n-3)×...×3×2×1`

= `(n+1)!`