# How do you simplify (n^3)^3*2n^-1 and write it using only positive exponents?

Sep 17, 2017

$2 {n}^{8}$

#### Explanation:

We have: ${\left({n}^{3}\right)}^{3} \cdot 2 {n}^{- 1}$

Using the laws of exponents:

$= {n}^{9} \cdot 2 {n}^{- 1}$

$= 2 \cdot {n}^{9} \cdot {n}^{- 1}$

$= 2 \cdot {n}^{9 + \left(- 1\right)}$

$= 2 \cdot {n}^{9 - 1}$

$= 2 \cdot {n}^{8}$

$= 2 {n}^{8}$