How do you simplify $((n-k)!) /( n!)$ ?

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Answer 1 · 2015-12-18T14:38:40

$((n-k)!)/(n!) = 1/((n-k+1)!)$

You simply develop $n!$ and $(n-k)!$ . $n-k < n$ so $(n-k)! < n!$ and $(n-k)!$ divides $n!$ .

All the terms of $(n-k)!$ are included in $n!$ , hence the answer.

How do you simplify ((n-k)!) /( n!)((n-k)!) /( n!)?