# How do you simplify r^2 - t^0?

Jun 2, 2015

r^2 - t^0 = ?#

Anything raised to the 0 is 1. Here is a quick example of why:

$\frac{{2}^{4}}{{2}^{1}} = \frac{16}{2} = {2}^{4 - 1} = {2}^{3} = 8$

Thus:

$\frac{{2}^{4}}{{2}^{4}} = \frac{16}{16} = {2}^{4 - 4} = {2}^{0} = 1$

So we just get:

${r}^{2} - \cancel{{t}^{0}} = {r}^{2} - 1$

And you can, yes, factor it out to be $\left(r - 1\right) \left(r + 1\right)$.