# How do you simplify (r^3t^-1x^-5)/(tx^5)?

Nov 7, 2016

${r}^{3} / \left({t}^{2} {x}^{10}\right)$

#### Explanation:

There are many different laws of indices. the 2 you need here are:

${x}^{-} m = \frac{1}{x} ^ m \text{ } \mathmr{and} {x}^{m} \times {x}^{n} = {x}^{m + n}$

I like to get rid of any negative indices first.

$\frac{{r}^{3} \textcolor{b l u e}{{t}^{-} 1} \textcolor{red}{{x}^{-} 5}}{t {x}^{5}} = \frac{{r}^{3}}{\textcolor{b l u e}{t} \cdot t {x}^{5} \textcolor{red}{{x}^{5}}}$

=${r}^{3} / \left({t}^{2} {x}^{10}\right)$

All the bases are different so there is no further simplifying possible.