# How do you simplify (s^-3 t^-5)/(s^2 t^3)^-1?

By exponential rules, we have that ${n}^{-} 1 = \frac{1}{n}$
$\frac{\frac{1}{{s}^{3} {t}^{5}}}{\frac{1}{{s}^{2} {t}^{3}}} = \frac{{s}^{2} {t}^{3}}{{s}^{3} {t}^{5}}$
Another exponential rule states that ${a}^{n} / {a}^{m} = {a}^{n - m}$.
${s}^{-} 1 {t}^{-} 2 = \frac{1}{s \cdot {t}^{2}}$