# How do you simplify s^-3/t^-5 using only positive exponents?

Jul 16, 2016

${s}^{- 3} / {t}^{- 5} = {t}^{5} / {s}^{3}$

#### Explanation:

One of the laws of indices states that:

${x}^{- m} = \frac{1}{x} ^ m$

If you move a base from the numerator to the denominator or vice versa, the sign of the index (exponent) changes.

So ${s}^{- 3} / {t}^{- 5} = {t}^{5} / {s}^{3}$