How do you simplify #sin(pi/2-x)/cos(pi/2-x)#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Feb 17, 2017

Answer:

#sin(pi/2-x)/cos(pi/2-x)=cotx#

Explanation:

As #sin(pi/2-x)=cosx# and #cos(pi/2-x)=sinx#

#sin(pi/2-x)/cos(pi/2-x)=cosx/sinx=cotx#

Was this helpful? Let the contributor know!
1500
Add an answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer
Impact of this question
Answer impact map
100 views around the world
You can reuse this answer
Creative Commons License