How do you simplify #-sqrt2*sqrt3#?

1 Answer

Answer:

#-sqrt (2) * sqrt (3) = -(sqrt (2) * sqrt (3))#

#sqrt (2) * sqrt (3) = sqrt (6)#

#=-sqrt (6) #

Explanation:

The equation is written as negative one multiplied by the square root of two multiplied by the square root of three.

To make it simpler, multiply the square roots first. This is done by putting the two numbers under the same square root symbol and simply multiplying.

This gives you the new value as the square root of 6.

After which you multiply by negative 1 to end up with the final answer as the negative of the value of the square root of 6.

NOTE:
This is not the same as the square root of negative 6 as an integer, as this will provide you with a complex number, while the negative of the value of the square root of 6 provides you with a real answer.