How do you simplify $\sqrt{4} (\frac{2^{2}}{4}) - 1$ $sqrt4(2^2/4)-1$ using order of operations?

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Answer 1 · 2015-12-03T12:23:50

$\sqrt{4} (\frac{2^{2}}{4}) - 1 = 1$ $sqrt4(2^2/4)-1=1$

$\sqrt{4} (\frac{2^{2}}{4}) - 1 = 2 \cdot \frac{4}{4} - 1$ $sqrt4(2^2/4)-1=2*4/4-1$
$= 2 \cdot 1 - 1$ $=2*1-1$
$= 2 - 1$ $=2-1$
$= 1$ $=1$

How do you simplify sqrt4(2^2/4)-1√4(224)−1sqrt4(2^2/4)-1 using order of operations?