# How do you simplify the expression (3x^2y^3)^ -2?

$\frac{1}{9 {x}^{4} {y}^{9}}$
$\frac{1}{3 {x}^{2} {y}^{3}} ^ 2$
$\frac{1}{9 {x}^{4} {y}^{9}}$