How do you simplify the expression #(4^0w^2)^-5# using the properties?
1 Answer
Apr 20, 2017
Explanation:
Using the
#color(blue)"laws of exponents"#
#• a^0=1#
#• (a^m)^n=a^(mn)#
#• a^-mhArr1/a^m#
#rArr(4^0w^2)^-5#
#=(1xxw^2)^-5=(w^2)^-5=w^(-10)=1/w^10#
