How do you simplify the expression #5(4+x)#?

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Answer 1 · 2017-04-22T21:12:50

#5x+20#

Multiply everything inside the brackets by the 5 that is outside of them. So we have

#color(green)(color(red)(5)(4+x)" "->" "color(red)(5)xx4" "+" "color(red)(5)xx x #

#" "20" "+" "5x#

Or you may if you wish write it as:

#5x+20#

Answer 2 · 2017-04-22T21:16:09

#5(4+x)=20+5x#

Simplify:

#5(4+x)#

Apply the distributive property: #a(b+c)=ab+ac#

#5*4+5*x=#

#20+5x#