How do you simplify the expression #csctheta/sintheta-cottheta/tantheta#?

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Answer 1 · 2016-10-02T02:44:30

#=>(1/sintheta)/sintheta - (costheta/sintheta)/(sintheta/costheta)#

#=>1/sintheta xx 1/sintheta - costheta/sintheta xx costheta/sintheta#

#=>1/sin^2theta - cos^2theta/sin^2theta#

#=> (1 - cos^2theta)/sin^2theta#

#=> sin^2theta/sin^2theta#

#=>1#

Hopefully this helps!