How do you simplify the expression #((r^2-9r)/(r^2+7r+10))/((r^2+5r)/(r^2+r-2))#?

2 Answers
Apr 10, 2017

Answer:

#((r-9))/((r+5))*((r-1))/((r+5))#

Explanation:

#((r(r-9))/((r+5)(r+2)))/((r(r+5))/((r-1)(r+2))#

#(r(r-9))/((r+5)(r+2))*((r-1)(r+2))/(r(r+5))#

#((r-9))/((r+5))*((r-1))/((r+5))#

If you want you can multiply this .. it's your turn

Apr 10, 2017

Answer:

#color(red)(((r-9)(r-1))/((r+5)(r+5))#

Explanation:

#((r^2-9r)/(r^2+7r+10))/((r^2+5r)/(r^2+r-2)#

#:.=((r^2-9r)/1 xx 1/(r^2+7r+10))-:((r^2+5r)/1 xx 1/(r^2+r-2))#

#:.=(r(r-9))/((r+2)(r+5))-:(r(r+5))/((r-1)(r+2))#

#:.=(r(r-9))/(cancel((r+2))(r+5)) xx ((r-1)cancel((r+2)))/(r(r+5)) #

#:.=(cancelr(r-9))/(r+5) xx ((r-1))/(cancelr(r+5)#

#:.=color(red)(((r-9)(r-1))/((r+5)(r+5))#