How do you simplify the expression #tanx/(tanx+tanxsinx)#?

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Answer 1 · 2016-11-02T13:25:53

#=> (sinx/cosx)/(sinx/cosx + sinx/cosxsinx#

#=>(sinx/cosx)/((sinx + sin^2x)/cosx)#

#=>sinx/cosx xx cosx/(sinx+ sin^2x)#

#=>sinx/(sinx + sin^2x)#

#=>sinx/(sinx(1 + sinx)#

#=>1/(1 + sinx)#

Hopefully this helps!