How do you simplify the expression #y^4/y^-7# using the properties?

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Answer 1 · 2017-07-18T05:46:05

#y^4/y^(-7)=y^11#

Given -

#y^4/y^(-7)#

#a^b = 1/a^(-b)#

Hence #1/y^(-7)=y^7#

Then

#y=y^4xxy^7=y^(4+7)=y^11#
#y^11#

Answer 2 · 2017-07-18T08:37:55

#y^11#

Recall the law of indices for division.

#x^m/x^n = x^(m-n)" "larr# subtract the indices

#y^4/y^-7 = y^(4-(-7)#

#=y^(4+7)#

#=y^11#

However, my first method of choice would be to change the negative index to a positive one by using the method shown by contributor nallasivan V