How do you simplify the expression #[(z^-2)^2]^3# using the properties? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer landon3 · Parabola Feb 2, 2018 #1/z^12# Explanation: First, #z^-n=1/z^n# So it becomes #[1/z^(2^2)]^3# Becuase #1^n=1# and #(a/b)^n=a^n/b^n# And #(a^b)^c=a^(bc)# Makes the equation #[1/z^4]^3# Using the last three again, we get #1/z^12# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1510 views around the world You can reuse this answer Creative Commons License