# How do you simplify the sum (8u^3+8u^2+6)+(4u^3-6u+3)?

May 13, 2018

$12 {u}^{3} + 8 {u}^{2} - 6 u + 9$

#### Explanation:

$\left(8 {u}^{3} + 8 {u}^{2} + 6\right) + \left(4 {u}^{3} - 6 u + 3\right)$

We can remove the parenthesis since we are just adding:
$8 {u}^{3} + 8 {u}^{2} + 6 + 4 {u}^{3} - 6 u + 3$

Now let's color-code the like terms which we will combine:
$\textcolor{red}{8 {u}^{3}} \quad \textcolor{g r e e n}{+ \quad 8 {u}^{2}} \quad \textcolor{b l u e}{+ \quad 6} \quad \textcolor{red}{+ \quad 4 {u}^{3}} \quad \textcolor{\mathmr{and} a n \ge}{- \quad 6 u} \quad \textcolor{b l u e}{+ \quad 3}$

$\textcolor{red}{12 {u}^{3}} \quad \textcolor{g r e e n}{+ \quad 8 {u}^{2}} \quad \textcolor{b l u e}{+ \quad 9} \quad \textcolor{\mathmr{and} a n \ge}{- \quad 6 u}$

Now write it in descending degree (higher to lower exponent in variable, with just the number at the end)

$12 {u}^{3} + 8 {u}^{2} - 6 u + 9$

Hope this helps!