# How do you simplify w^-2 + 1/ w^-5?

Apr 4, 2015

If by simply, you mean write without negative exponents, the answer is $\frac{1 + {w}^{7}}{w} ^ 2$

We can rewrite $\frac{1}{w} ^ - 5$ as ${w}^{5}$:
${w}^{-} 2 + {w}^{5}$

Factor out the lowest degree:
${w}^{-} 2 \left(1 + {w}^{7}\right)$

We can rewrite ${w}^{-} 2$ as $\frac{1}{w} ^ 2$
$\frac{1 + {w}^{7}}{w} ^ 2$