How do you simplify without negative exponents (b^2)^-6/b^-4?

Oct 19, 2015

The answer is $\frac{1}{b} ^ 8$.

Explanation:

${\left({b}^{2}\right)}^{-} \frac{6}{b} ^ - 4$

Simplify.

Apply exponent rule ${\left({a}^{m}\right)}^{n} = {a}^{m \cdot n}$

${b}^{- 12} / {b}^{-} 4$

Apply quotient rule ${a}^{m} / {a}^{n} = {a}^{m - n}$

b^(-12-(-4)=

${b}^{- 12 + 4} =$

${b}^{-} 8$

Apply the negative exponent rule ${a}^{- m} = \frac{1}{a} ^ m$.

${b}^{- 8} = \frac{1}{b} ^ 8$