How do you simplify #(x+1)/x - x/(x+1)#?

3 Answers
May 18, 2018

#(2x+1)/(x(x+1)#

Explanation:

Find the lowest common factor which is #x(x+1)#

#(x+1)/x = x/(x+1)#

#((x+1)(x+1) - (x xx x))/(x(x+1))#

#(x^2+x+x+1 - x^2)/(x(x+1)#

#(cancel(x^2-x^2)+2x+1)/(x(x+1)#

#(2x+1)/(x(x+1)#

May 18, 2018

#(2x+1)/(x(x+1))#

Explanation:

#"we require the fractions to have a "color(blue)"common denominator"#

#"to obtain this"#

#"multiply the numerator/denominator of "(x+1)/x#
#"by "(x+1)#

#"and multiply numerator/denominator of "x/(x+1)" by "x#

#=((x+1)(x+1))/(x(x+1))-x^2/(x(x+1))#

#"the fractions now have a common denominator so expand"#
#"and subtract the numerator leaving the denominator"#

#=(cancel(x^2)+2x+1cancel(-x^2))/(x(x+1))#

#=(2x+1)/(x(x+1))#

May 18, 2018

#(x+1)/x - x/(x+1) = 1/x+1/(x+1)#

Explanation:

I am not sure what is meant by simplified here, but we can find:

#(x+1)/x - x/(x+1) = (x+1)/x-((x+1-1)/(x+1))#

#color(white)((x+1)/x - x/(x+1)) = (1+1/x)-(1-1/(x+1))#

#color(white)((x+1)/x - x/(x+1)) = 1/x+1/(x+1)#