How do you simplify #(x^2-14x+48)/(x^2-6x)div(3x-24)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Binayaka C. Dec 24, 2016 #1/(3x)# Explanation: #(x^2-14x+48)/(x^2-6x)/(3x-24) = (x^2-14x+48)/(x^2-6x) * 1/(3x-24) = (cancel((x-8))cancel((x-6)))/(xcancel((x-6))* 3cancel((x-8)) )=1/(3x)#[Ans] Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 2327 views around the world You can reuse this answer Creative Commons License