# How do you simplify (x^2 - 16)/(x^2 - 4x)?

$\frac{{x}^{2} - 16}{{x}^{2} - 4 x} = \frac{\cancel{\left(x - 4\right)} \left(x + 4\right)}{\cancel{\left(x - 4\right)} x} = \frac{x + 4}{x}$
$= \frac{x}{x} + \frac{4}{x} = 1 + \frac{4}{x}$
With the restrictions that $x \ne 0$ and $x \ne 4$