How do you simplify #(x^2-25) / (2x) div (x^2 + 6x+5) / (4x^2)#?

1 Answer
May 22, 2017

Answer:

First we change this into a multiplication, by inverting the second term.

Explanation:

Inverting means swapping the stuff below and above the division bar:

#=(x^2-25)/(2x)xx(4x^2)/(x^2+6x+5)#

Now, if we factorize, we may cancel some parts:

#=(cancel((x+5))(x-5))/(cancel(2x))xx((2x*cancel(2x)))/((x+1)cancel((x+5)))#

#=(2x(x-5))/(x+1)=(4x^2-10x)/(x+1)#