How do you simplify #(x^2-3x+2)/(x^2+5x-6)#?
1 Answer
Sep 7, 2016
Explanation:
The first step is to factorise both numerator and denominator.
Both are quadratics and can be factorised using the a-c method.
#rArrx^2-3x+2=(x-2)(x-1)# and
#x^2+5x-6=(x+6)(x-1)#
#rArr(x^2-3x+2)/(x^2+5x-6)=((x-2)(cancel(x-1)))/((x+6)(cancel(x-1)))=(x-2)/(x+6)#
