How do you simplify #(x^2)^4*3x^5# and write it using only positive exponents?

1 Answer

Answer:

#3x^13#

Explanation:

We have

#(x^2)^4xx3x^5#

We can rewrite the first term using the rule #(x^a)^b=x^(ab)#:

#x^8xx3x^5#

Before we go further combining x terms, let's work with the 3. I'll do that by rewriting the equation this way:

#x^8xx3x^5=x^8xx3 xx x^5#

We can now combine the x terms using the rule #x^a xx x^b=x^(a+b)#

#x^13xx3#

and this just simplifies down to

#3x^13#