# How do you simplify (x^2)^4*3x^5 and write it using only positive exponents?

$3 {x}^{13}$

#### Explanation:

We have

${\left({x}^{2}\right)}^{4} \times 3 {x}^{5}$

We can rewrite the first term using the rule ${\left({x}^{a}\right)}^{b} = {x}^{a b}$:

${x}^{8} \times 3 {x}^{5}$

Before we go further combining x terms, let's work with the 3. I'll do that by rewriting the equation this way:

${x}^{8} \times 3 {x}^{5} = {x}^{8} \times 3 \times {x}^{5}$

We can now combine the x terms using the rule ${x}^{a} \times {x}^{b} = {x}^{a + b}$

${x}^{13} \times 3$

and this just simplifies down to

$3 {x}^{13}$