Question

How do you simplify `(x^2 - 4x + 4 - y^2)/( 2x^2 - 11x + 15) * (x^4 y)/ (x- 2 + y) div (x^3 y - 2x^2y - x^2 y^2)/( 3x -9)`?

Answer 1

`(3x^2)/((2x-5)`

Explanation:

`(x^2-4x+4-y^2)/(2x^2-11x+15)``(x^4y)/(x-2+y)``((x^3y-2x^2y-x^2y^2)/(3x-9))^(-1)`

=`((x-2)^2-y^2)/(2x^2-11x+15)``(x^4y)/(x-2+y)`# (3x-9)/(x^3y-2x^2y-x^2y^2)#

=`((x-2+y)(x-2-y))/((2x-5)(x-3))``(x^4y)/(x-2+y)`# (3(x-3))/(x^2y(x-2-y))#

=`(3x^2)/((2x-5)`