Question

How do you simplify `(x^2+4x-5)/(5x^2-8x+3) div (20x-12)/(x^2-6x-55)`?

Answer 1

Simplify quadratic expression f(x)

Explanation:

First factor all 3 trinomials:
x^2 + 4x - 5 = (x - 1)(x + 5)
5x^2 - 8x + 3 = (x - 1)(5x - 3)
x^2 - 6x - 55) = (x + 5)(x - 11)
and factor the binomial: 20x - 12 = 4(5x - 3).

`f(x) = ((x - 1)(x + 5))/((x - 1)(5x - 3)).((x + 5)(x - 11))/(4(5x - 3)) =`

`= ((x + 5)^2(x - 11))/(4(5x - 3)^2`