# How do you simplify (x^2+4x-5)/(5x^2-8x+3) div (20x-12)/(x^2-6x-55)?

##### 1 Answer
Jul 29, 2015

Simplify quadratic expression f(x)

#### Explanation:

First factor all 3 trinomials:
x^2 + 4x - 5 = (x - 1)(x + 5)
5x^2 - 8x + 3 = (x - 1)(5x - 3)
x^2 - 6x - 55) = (x + 5)(x - 11)
and factor the binomial: 20x - 12 = 4(5x - 3).

$f \left(x\right) = \frac{\left(x - 1\right) \left(x + 5\right)}{\left(x - 1\right) \left(5 x - 3\right)} . \frac{\left(x + 5\right) \left(x - 11\right)}{4 \left(5 x - 3\right)} =$

= ((x + 5)^2(x - 11))/(4(5x - 3)^2