How do you simplify (x^(2/5)y)/(xy^(-1/3))?

A1. You have more x's in the denominator. ${x}^{1} - {x}^{\frac{2}{5}}$=${x}^{\frac{3}{5}}$
--> y/(x^(3/5)y^(-1/3)
Q2. What do we do with the ${y}^{- \frac{1}{3}}$ in the denominator?
--> (y*y^(1/3))/(x^(3/5) = ${y}^{\frac{4}{3}} / {x}^{\frac{3}{5}}$