# How do you simplify (x^2+6x+11)+(3x^2+7x+4)?

${x}^{2} + 6 x + 11 + 3 {x}^{2} + 7 x + 4 \implies$
${x}^{2} + 3 {x}^{2} + 6 x + 7 x + 11 + 4 \implies$
$\left(1 + 3\right) {x}^{2} + \left(6 + 7\right) x + 14 \implies$
$4 {x}^{2} + 13 x + 14$