# How do you simplify  (x^2-9)/(x^2+3x)?

We have that $\frac{{x}^{2} - 9}{{x}^{2} + 3 x} = \frac{\left(x - 3\right) \left(x + 3\right)}{x \left(x + 3\right)} = \frac{x - 3}{x}$