# How do you simplify (x^2/t)^3 and write it using only positive exponents?

#### Answer:

${\left({x}^{2} / t\right)}^{3} = {x}^{2 \times 3} / {t}^{1 \times 3} = {x}^{6} / {t}^{3}$

#### Explanation:

Remember that ${\left({x}^{a}\right)}^{b} = {x}^{a b}$

and just for fun, let's check:

${\left({2}^{2}\right)}^{3} = {4}^{3} = 64 \mathmr{and} {\left({2}^{2}\right)}^{3} = {2}^{2 \times 3} = {2}^{6} = 64$

So in the question:

${\left({x}^{2} / t\right)}^{3}$ we are cubing the top and bottom, like so:

${\left({x}^{2} / t\right)}^{3} = {x}^{2 \times 3} / {t}^{1 \times 3} = {x}^{6} / {t}^{3}$