How do you simplify #(x-2)/(x^2-8x+12 )#?

1 Answer
Sep 29, 2015

Answer:

#1/(x-6)#

Explanation:

First, factor the denominator completely.

#(x-2)/(x^2-8x+12)#
#=(x-2)/((x-2)(x-6))#
#=cancel(x-2)/(cancel((x-2))(x-6))#
#color(blue)(=1/(x-6))#

WARNING: You can simplify this, however, take note that you have canceled out #(x-2)# in the denominator. If you are asked for the domain, make sure that #color(red)(x-2!=0)# or #color(red)(x!=2)#.