How do you simplify #(x^2 – x – 6 )/(x^2 – 9x + 18 )#?
1 Answer
Apr 23, 2016
#(x^2-x-6)/(x^2-9x+18)=(x+2)/(x-6)=1+8/(x-6)#
excluding
Explanation:
Factor the numerator and denominator. Cancel the common factor
#(x^2-x-6)/(x^2-9x+18)#
#=(color(red)(cancel(color(black)((x-3))))(x+2))/(color(red)(cancel(color(black)((x-3))))(x-6))#
#=(x+2)/(x-6)#
#=(x-6+8)/(x-6)#
#=1+8/(x-6)#
excluding
The value