# How do you simplify ( x^2 )/(xy^-4)*(2x^-3y^4)/( 3xy^-1)?

Jun 3, 2015

$\frac{2 {y}^{9}}{3 {x}^{3}}$

#### Explanation:

$\frac{{x}^{2}}{x {y}^{-} 4} \cdot \frac{2 {x}^{-} 3 {y}^{4}}{3 x {y}^{-} 1}$

We start by moving the negative exponents into positive reciprocals.

$\frac{{x}^{2} {y}^{4}}{x} \cdot \frac{2 {y}^{5}}{3 {x}^{4}}$

We can cancel a ${x}^{2}$ from the numerator and denominator.
${y}^{4} / x \cdot \frac{2 {y}^{5}}{3 {x}^{2}}$

$\frac{2 {y}^{9}}{3 {x}^{3}}$