How do you simplify #((x^2-y^2)(x^2+xy+y^2))/((x^3-y^3)(x^2+2xy+y^2))#?
It simplifies to
First, factor the bottom right and top left polynomials using the special binomial factoring cases:
Cancel the common factor:
Next, use the difference of cubes product to factor the bottom left polynomial:
Cancel the common factors again:
That's as simplified as it gets. Hope this helped!
I'll use the following formulas:
#color(blue)(x^2 - y^2 = (x+y)(x-y))#
#color(purple)(x^3 - y^3 = (x-y)(x^2 + xy + y^2))#
#color(green)((x+y)^2 = x^2 + 2xy + y^2)#