How do you simplify #(x^2x^3)^4# and write it using only positive exponents?
1 Answer
May 29, 2017
Answer:
Explanation:
There are three laws of indices at play here.

#(x^a xx y^b)^m = x^(am) xx y^(bm)# 
#x^m = 1/x^m# 
#x^m xx x^n = x^(m+n)#
It does not matter which law you apply first!
I will choose to get rid of the bracket by multiplying the indices.
Add the indices of like bases: