# How do you simplify (x^2y^4m^3)^8 and write it using only positive exponents?

Feb 3, 2017

See the entire simplification process below:

#### Explanation:

Use this rule of exponents to simplify this expression:

${\left({x}^{\textcolor{red}{a}}\right)}^{\textcolor{b l u e}{b}} = {x}^{\textcolor{red}{a} \times \textcolor{b l u e}{b}}$

${\left({x}^{\textcolor{red}{2}} {y}^{\textcolor{red}{4}} {m}^{\textcolor{red}{3}}\right)}^{\textcolor{b l u e}{8}} = {x}^{\textcolor{red}{2} \times \textcolor{b l u e}{8}} {y}^{\textcolor{red}{4} \times \textcolor{b l u e}{8}} {m}^{\textcolor{red}{3} \times \textcolor{b l u e}{8}} = {x}^{16} {y}^{32} {m}^{24}$

Because all of the exponents are already positive there is nothing else need to complete this problem.