How do you simplify #x / 3 - 2 / 3 = 1 / x#?

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Answer 1 · 2018-05-11T03:30:08

#color(green)(x = 3, -1#

#x/3 - 2/3 = 1/x#

#(x-2) / 3 = 1/x " taking 3 as L C M for L H S"#

#(x - 2) * x = 3 * 1, " cross multiplying"#

#x^2 - 2x = 3, " removing bracket"#

#x^2 - 2x - 3 = 0#

#x^2 + x - 3x - 3 = 0#

#x (x + 1) - 3 (x + 1) = 0#

# (x-3) * (x + 1) = 0#

#color(green)(x = 3, -1#